QUESTION IMAGE
Question
- complete the proof.
given: \\( \triangle a b o \\) and \\( \triangle d e o \\) are right \\( \delta \mathrm{s} ; \overline{a b} \cong \overline{d e} ; \overline{a b} \\| \overline{d e} \\).
prove: \\( \triangle a b o \cong \triangle d e o \\)
statements
- \\( \triangle a b o \\) and \\( \triangle d e o \\) are right \\( \delta \mathrm{s} \\); \\( \overline{a b} \cong \overline{d e} ; \overline{a b} \\| \overline{d e} \\).
- \\( \angle a \cong \angle d \\)
- \\( \triangle a b o \cong \triangle d e o \\)
reasons
- given
- \\( \overline{a d} \\) is a transversal cutting parallel segments \\( \overline{a b} \\) and \\( \overline{d e} \\).
3.
Step1: Find reason for ∠A ≅ ∠D
When two parallel lines (\(\overline{AB}\) and \(\overline{DE}\)) are cut by a transversal (\(\overline{AD}\)), the alternate interior angles are congruent. So the reason for \(∠A\cong∠D\) is "Alternate Interior Angles Theorem".
Step2: Prove \(\triangle ABO\cong\triangle DEO\)
We have two right triangles (\(\triangle ABO\) and \(\triangle DEO\)), \(∠A\cong∠D\) (from step 1), \(\overline{AB}\cong\overline{DE}\) (given). By the Angle - Side - Angle (ASA) congruence criterion for right triangles (since the right angles \(∠B\) and \(∠E\) are also congruent as they are right angles (\(90^{\circ}\)) and we have a side and two angles), \(\triangle ABO\cong\triangle DEO\).
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- Alternate Interior Angles Theorem; 3. ASA (Angle - Side - Angle)