Question

complete the proof.
given: \\( \overline { wz } \cong \overline { zs } \cong \overline { sd } \cong \overline { dw } \\)
prove: \\( \triangle wzd \cong \triangle sdz \\)

complete the proof below.

statement	reasons
2. \\( \overline { wd } \cong \overline { sz } \\)	2. given
3. \\( \overline { zd } \cong \overline { zd } \\)	3. given

Explanation:

Step1: Identify the property for \( \overline{ZD}\cong\overline{ZD} \)

The reflexive property of congruence states that any segment is congruent to itself. So, for the statement \( \overline{ZD}\cong\overline{ZD} \), the reason is the reflexive property of \( \cong \).

Answer:

The reason for \( \overline{ZD}\cong\overline{ZD} \) is "Reflexive property of \( \cong \)"