QUESTION IMAGE
Question
complete the proof that \\( \triangle vwx \cong \triangle uty \\).
Step1: Identify the reason for \(\overline{XY}\cong\overline{UV}\)
From the figure, the segments \(\overline{XY}\) and \(\overline{UV}\) are marked with the same number of tick - marks. So the reason is "Given (marked on the diagram)".
Step2: Identify the reason for \(\overline{VW}\cong\overline{TU}\)
The segments \(\overline{VW}\) and \(\overline{TU}\) are marked with the same number of tick - marks. So the reason is "Given (marked on the diagram)".
Step3: Identify the reason for \(\overline{TY}\cong\overline{WX}\)
The segments \(\overline{TY}\) and \(\overline{WX}\) are marked with the same number of tick - marks. So the reason is "Given (marked on the diagram)".
Step4: Identify the reason for \(UY = XY+UX\)
By the segment addition postulate (if we have two adjacent segments \(XY\) and \(UX\) that form a larger segment \(UY\)). So the reason is "Segment Addition Postulate".
Step5: Identify the reason for \(VX = UV + UX\)
By the segment addition postulate (if we have two adjacent segments \(UV\) and \(UX\) that form a larger segment \(VX\)). So the reason is "Segment Addition Postulate".
Step6: Identify the reason for \(UY=UV + UX\)
Since \(XY\cong\overline{UV}\), then \(XY = UV\). Substitute \(XY\) with \(UV\) in the equation \(UY=XY + UX\) (by substitution property of equality). So the reason is "Substitution Property (\(XY = UV\))".
Step7: Identify the reason for \(VX = UY\)
Since \(VX=UV + UX\) and \(UY = UV+UX\), by transitive property of equality (if \(a=b\) and \(b = c\), then \(a=c\)). So the reason is "Transitive Property (\(VX=UV + UX\) and \(UY = UV + UX\))".
Step8: Identify the reason for \(\triangle VWX\cong\triangle UTY\)
We have \(\overline{VW}\cong\overline{TU}\), \(\overline{WX}\cong\overline{TY}\), and \(\overline{VX}\cong\overline{UY}\). By SSS (Side - Side - Side) congruence criterion. So the reason is "SSS Congruence Criterion".
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- Given (marked on the diagram)
- Given (marked on the diagram)
- Given (marked on the diagram)
- Segment Addition Postulate
- Segment Addition Postulate
- Substitution Property (\(XY = UV\))
- Transitive Property (\(VX=UV + UX\) and \(UY = UV + UX\))
- SSS Congruence Criterion