complete the following sentence. the figure below rotational symmetry. has does not have

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# Brief Explanations:
A figure has rotational symmetry if rotating it about its center by a certain angle (less than 360°) maps it onto itself. The given figure is an isosceles triangle (or possibly an equilateral triangle? Wait, no, the base is horizontal and the two equal sides are the legs? Wait, no, the triangle here—if it's an isosceles triangle (with two equal sides and a base), rotating it by 180°? Wait, no, actually, an isosceles triangle (non - equilateral) has rotational symmetry of order 1? Wait, no, rotational symmetry order: the number of times it maps onto itself when rotated 360°. For a non - equilateral isosceles triangle, rotating it by 180° does not map it onto itself. Wait, but wait, the triangle in the image—if it's an isosceles triangle (with the two equal sides as the legs from the base). Wait, actually, the correct approach: rotational symmetry. Let's recall: a figure has rotational symmetry if there exists a rotation (other than 360°) that maps the figure to itself. For a triangle: an equilateral triangle has rotational symmetry of order 3 (rotating by 120°, 240°). A non - equilateral isosceles triangle: does it have rotational symmetry? Let's think about the given triangle. The triangle in the image—if we rotate it by 180° around its center (the centroid or the center of the base? Wait, no, the center of rotation for rotational symmetry is the center of the figure. For a triangle, the center of rotation would be the intersection of the medians. If we rotate the isosceles triangle (non - equilateral) by 180°, the top vertex would go to the base, and the base vertices would go to the top, but since the two equal sides are not equal to the base (in a non - equilateral isosceles triangle), it won't map onto itself. Wait, but wait, maybe the triangle is equilateral? No, the drawing looks like an isosceles triangle with the two equal sides being the left and right sides, and the base horizontal. Wait, no, actually, the key: the triangle shown—if we consider rotational symmetry. Wait, no, I think I made a mistake. Wait, an isosceles triangle (including equilateral) —wait, no, the correct answer: the triangle (assuming it's isosceles, non - equilateral) does not have rotational symmetry? Wait, no, wait, no—wait, the triangle in the image: let's check. If we rotate it by 180 degrees around the midpoint of the base. Wait, the midpoint of the base: if we rotate the triangle 180 degrees around that midpoint, the top vertex will swap with the midpoint? No, that's not right. Wait, maybe the triangle is equilateral? No, the drawing has a base and two equal sides, looking like an isosceles triangle. Wait, no, the correct concept: rotational symmetry. A figure has rotational symmetry when it can be rotated by an angle between 0° and 360° (excluding 360°) and still look the same. For a non - equilateral isosceles triangle, there is no such angle. So the triangle does not have rotational symmetry? Wait, no, wait, I think I messed up. Wait, the triangle in the image—let's see, the triangle is isosceles. Rotational symmetry: if we rotate it by 180 degrees, does it map onto itself? Let's imagine: the top vertex is at the top, the base is at the bottom. Rotating 180 degrees around the center (the center of the triangle) would move the top vertex to the bottom, and the two base vertices to the top. But since the two base vertices are symmetric with respect to the vertical axis, and the top vertex is on the vertical axis, rotating 180 degrees would flip the triangle vertically. Wait, no, rotation is a turn, not a flip. So rotating 180 degrees around the center (the centroid) would move each point (x,y) to (-x, -y) if the centroid is at (0,0). For the isosceles triangle with vertices at (0, h), ( - b, 0), (b, 0), rotating 180 degrees around (0,0) would map (0, h) to (0, - h), and (-b, 0) to (b, 0), (b, 0) to (-b, 0). But (0, - h) is not a vertex of the original triangle (since the original triangle has vertex at (0, h) and base at y = 0). So it does not map onto itself. Therefore, the triangle does not have rotational symmetry? Wait, but wait, the answer—wait, maybe the triangle is equilateral? No, the drawing doesn't look equilateral. Wait, maybe I'm wrong. Wait, let's recall: rotational symmetry. The definition is that a figure has rotational symmetry if there is a rotation (other than 360°) that maps the figure to itself. For the given triangle (isosceles, non - equilateral), there is no such rotation. So the figure does not have rotational symmetry.
# Answer:
does not have

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