Question

∠1 is a complement of ∠2, and ( m∠1 = 23^{circ} ). find ( m∠2 ). ( m∠2 = square^{circ} )

Explanation:

Step1: Recall the definition of complementary angles

If two angles are complementary, then the sum of their measures is \(90^{\circ}\). So, \(m\angle1 + m\angle2=90^{\circ}\).

Step2: Solve for \(m\angle2\)

Given \(m\angle1 = 23^{\circ}\), substitute into the equation: \(m\angle2=90^{\circ}-m\angle1\).
Substitute \(m\angle1 = 23^{\circ}\) into the formula: \(m\angle2 = 90^{\circ}-23^{\circ}\).
Calculate \(90 - 23\): \(m\angle2=67^{\circ}\).

Answer:

\(67\)