Question

comparing shapes
here is a triangle and two parallelograms from the previous screen.
a. drag the point to compare the shapes.
b. what is the relationship between the areas of these three shapes?

Explanation:

Step1: Recall area formulas

Area of triangle $A_{t}=\frac{1}{2}bh$, area of parallelogram $A_{p}=bh$.

Step2: Assume same - base and height

If the triangle and parallelograms have the same base $b$ and height $h$.
The area of the triangle $A_{L}=\frac{1}{2}bh$.
The area of parallelogram $M$ and $N$ (assuming same base and height) is $A_{M}=A_{N}=bh$.

Step3: Determine relationship

The area of each parallelogram is twice the area of the triangle.

Answer:

The area of each parallelogram (M and N) is twice the area of the triangle (L).