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Question
college prep the base of isosceles △xyz is (overline{yz}). what can you prove? select all that apply.
(squareoverline{xy}congoverline{xz})
(squareangle xcongangle y)
(squareangle ycongangle z)
(squareoverline{yz}congoverline{zx})
In an isosceles triangle, the sides opposite the base are equal. Since \( \overline{YZ} \) is the base of \( \triangle XYZ \), the legs \( \overline{XY} \) and \( \overline{XZ} \) are equal (\( \overline{XY}\cong\overline{XZ} \)). Also, in an isosceles triangle, the base angles (the angles opposite the equal sides) are equal. The base angles here are \( \angle Y \) and \( \angle Z \), so \( \angle Y\cong\angle Z \).
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\(\overline{XY}\cong\overline{XZ}\), \(\angle Y\cong\angle Z\)