Question

coefficient of friction worksheet

1. a hockey puck has a coefficient of kinetic friction of $\mu_{k}=.10$. if the puck feels a normal force ($f_{n}$) of 5 n, what is the frictional force that acts on the puck?

Explanation:

Step1: Recall the formula for kinetic frictional force

The formula for kinetic frictional force \(F_f=\mu_kF_N\), where \(\mu_k\) is the coefficient of kinetic friction and \(F_N\) is the normal force.

Step2: Substitute the given values into the formula

Given \(\mu_k = 0.10\) and \(F_N=5\space N\). Substitute these values into the formula: \(F_f=(0.10)\times(5)\).

Step3: Calculate the frictional force

\(F_f = 0.5\space N\)

Answer:

\(0.5\space N\)