Question

1. circle the points that are on the graph of ( 2x + 3y = 60 ). draw a line through the points that are not on the graph. be ready to show/explain how you know whether or not each point is on the graph.

( (12,12) )
( (-9,26) )
( (30,20) )
( left(26,\frac{8}{3}
ight) )

Explanation:

Step1: Substitute \((12,12)\) into \(2x + 3y\)

Substitute \(x = 12\) and \(y=12\) into \(2x + 3y\).
\(2\times12+3\times12=24 + 36=60\)

Step2: Substitute \((-9,26)\) into \(2x + 3y\)

Substitute \(x=-9\) and \(y = 26\) into \(2x+3y\).
\(2\times(-9)+3\times26=-18 + 78=60\)

Step3: Substitute \((30,20)\) into \(2x + 3y\)

Substitute \(x = 30\) and \(y=20\) into \(2x+3y\).
\(2\times30+3\times20=60+60 = 120
eq60\)

Step4: Substitute \((26,\frac{8}{3})\) into \(2x + 3y\)

Substitute \(x = 26\) and \(y=\frac{8}{3}\) into \(2x+3y\).
\(2\times26+3\times\frac{8}{3}=52 + 8=60\)

Answer:

Circle \((12,12)\), \((-9,26)\), \((26,\frac{8}{3})\); draw a line through \((30,20)\)