Question

checkpoint graph the equation 4. x = 2 5. x = -1 6. x = 3 1/2

Explanation:

Step1: Analyze the equation type

The equations \(x = 2\), \(x=-1\) and \(x = 3\frac{1}{2}\) are all vertical - line equations of the form \(x = a\), where \(a\) is a constant.

Step2: Graph the first equation \(x = 2\)

On a coordinate plane, draw a vertical line passing through the point \((2,0)\). All points on this line have an \(x\) - coordinate of 2 and \(y\) can take any real - value.

Step3: Graph the second equation \(x=-1\)

Draw a vertical line passing through the point \((-1,0)\). All points on this line have an \(x\) - coordinate of \(-1\) and \(y\) can be any real number.

Step4: Graph the third equation \(x = 3\frac{1}{2}=\frac{7}{2}\)

Draw a vertical line passing through the point \((\frac{7}{2},0)\). All points on this line have an \(x\) - coordinate of \(\frac{7}{2}\) and \(y\) can be any real number.

Answer:

For \(x = 2\), graph a vertical line through \((2,0)\); for \(x=-1\), graph a vertical line through \((-1,0)\); for \(x = 3\frac{1}{2}\), graph a vertical line through \((\frac{7}{2},0)\).