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category: quiz
current learning objective: using arrow notation
question 19 practice similar questions
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describe the local behavior of ( f(x)=-\frac{3}{x^{2}} )
a as ( x
ightarrow 0^{+}, f(x)
ightarrow-infty ), and as ( x
ightarrow 0^{-}, f(x)
ightarrow infty )
b as ( x
ightarrow 0^{+}, f(x)
ightarrow-infty ), and as ( x
ightarrow 0^{-}, f(x)
ightarrow-infty )
c as ( x
ightarrow 0^{+}, f(x)
ightarrow infty ), and as ( x
ightarrow 0^{-}, f(x)
ightarrow-infty )
d as ( x
ightarrow 0^{+}, f(x)
ightarrow infty ), and as ( x
ightarrow 0^{-}, f(x)
ightarrow infty )
submit answer attempts: 0/2
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Step1: Analyze \(x\to0^{+}\)
When \(x\to0^{+}\), \(x^{2}\to0^{+}\) (since \(x>0\) and approaching \(0\), \(x^{2}\) is positive and approaching \(0\)). Then \(\frac{3}{x^{2}}\to+\infty\). So \(f(x)=-\frac{3}{x^{2}}\to-\infty\).
Step2: Analyze \(x\to0^{-}\)
When \(x\to0^{-}\), \(x^{2}\to0^{+}\) (because \(x < 0\), \(x^{2}=(-|x|)^{2}=|x|^{2}\), and as \(x\to0^{-}\), \(|x|\to0\), so \(x^{2}\to0^{+}\)). Then \(\frac{3}{x^{2}}\to+\infty\). So \(f(x)=-\frac{3}{x^{2}}\to-\infty\).
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B. as \(x\to0^{+},f(x)\to-\infty\), and as \(x\to0^{-},f(x)\to-\infty\)