Question

if a car travels 30.0 mi. north for 30.0 min., 50.0 mi. east for 1.00 hour, and 30.0 mi. south for 30.0 min., what is the average speed of the car over the total trip?
60.0 mph

1. mph

55 mph
55.0 mph

Explanation:

Step1: Calculate total distance

First, find the total distance traveled. The car goes 30.0 mi north, 50.0 mi east, and 30.0 mi south. So total distance \( d = 30.0 + 50.0 + 30.0 = 110.0 \) mi.

Step2: Calculate total time

Next, find the total time. 30.0 min is 0.5 hours, 1.00 hour, and another 30.0 min (0.5 hours). So total time \( t = 0.5 + 1.00 + 0.5 = 2.00 \) hours.

Step3: Calculate average speed

Average speed is total distance divided by total time. So average speed \( v = \frac{d}{t} = \frac{110.0}{2.00} = 55.0 \) mph.

Answer:

55.0 mph