Question

a cannonball is fired from the ground at an angle above the horizontal. during the flight of the cannon ball the magnitude of the cannon balls acceleration a remains the same b decreases and then increases c increases and then decreases

Explanation:

Step1: Analyze the motion of the cannonball

The cannonball is in projectile motion. In projectile motion (neglecting air - resistance), the only force acting on the cannonball is the gravitational force \(F = mg\).

Step2: Apply Newton's second law \(F = ma\)

Since \(F=mg\) and \(F = ma\), then \(a=\frac{F}{m}=\frac{mg}{m}=g\). The acceleration due to gravity \(g\approx9.8\ m/s^{2}\) near the Earth's surface and acts vertically downwards throughout the flight of the cannonball.

Answer:

A. Remains the same