Question

calculating kinetic energy
a conveyer belt moves a 40 kg box at a velocity of 2 m/s. what is the kinetic energy of the box while it is on the conveyor belt?
○ 40 j
○ 80 j
○ 160 j
○ 1,600 j

Explanation:

Step1: Recall the kinetic energy formula

The formula for kinetic energy (KE) is $KE = \frac{1}{2}mv^2$, where $m$ is the mass and $v$ is the velocity.

Step2: Identify the given values

Here, $m = 40\space kg$ and $v = 2\space m/s$.

Step3: Substitute the values into the formula

Substitute $m = 40$ and $v = 2$ into $KE=\frac{1}{2}mv^2$:
$$KE=\frac{1}{2}\times40\times(2)^2$$
First, calculate $(2)^2 = 4$. Then, $\frac{1}{2}\times40 = 20$. Now, multiply $20\times4 = 80$.

Answer:

80 J (corresponding to the option "80 J")