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Question
calculating force using hooke’s law
how much force is necessary to stretch a spring 0.5 m when the spring constant is 190 n/m?
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Step1: Recall Hooke's Law formula
Hooke's Law is given by \( F = kx \), where \( F \) is the force, \( k \) is the spring constant, and \( x \) is the displacement.
Step2: Substitute the given values
We know that \( k = 190 \, \text{N/m} \) and \( x = 0.5 \, \text{m} \). Substituting these into the formula: \( F = 190 \times 0.5 \)
Step3: Calculate the force
\( 190 \times 0.5 = 95 \)
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