QUESTION IMAGE
Question
calculate the volume of the composite shape shown above. use 3.1416 for the approximate value of π. round your answer to two decimal places, as needed.
$v_{\text{cone}} = \boxed{\quad} \text{cm}^3$
$v_{\text{cylinder}} = \boxed{\quad} \text{cm}^3$
$v_{\text{hemisphere}} = \boxed{\quad} \text{cm}^3$
$v_{\text{total}} \boxed{\quad} \text{cm}^3$
Step1: Find the radius of the sphere, cylinder, and cone
The diameter is 12 cm, so the radius \( r = \frac{12}{2} = 6 \) cm.
Step2: Calculate the volume of the cone
The formula for the volume of a cone is \( V_{\text{cone}} = \frac{1}{3}\pi r^2 h \). Here, \( r = 6 \) cm and \( h = 9 \) cm.
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Step3: Calculate the volume of the cylinder
The formula for the volume of a cylinder is \( V_{\text{cylinder}} = \pi r^2 h \). Here, \( r = 6 \) cm and \( h = 18 \) cm.
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Step4: Calculate the volume of the hemisphere
The formula for the volume of a sphere is \( \frac{4}{3}\pi r^3 \), so the volume of a hemisphere is \( \frac{2}{3}\pi r^3 \). Here, \( r = 6 \) cm.
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Step5: Calculate the total volume
Add the volumes of the cone, cylinder, and hemisphere.
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Rounding to two decimal places, \( V_{\text{total}} \approx 2827.21 \)
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\( V_{\text{cone}} = 339.29 \) \( \text{cm}^3 \)
\( V_{\text{cylinder}} = 2035.75 \) \( \text{cm}^3 \)
\( V_{\text{hemisphere}} = 452.17 \) \( \text{cm}^3 \)
\( V_{\text{total}} = 2827.21 \) \( \text{cm}^3 \)
(Note: The slight differences in the hemisphere and total volume are due to rounding at each step. If we round only at the end, the hemisphere volume is 452.1696 ≈ 452.17, and the total is 339.2928 + 2035.752 + 452.1696 = 2827.2144 ≈ 2827.21)