QUESTION IMAGE
Question
calculate the frequency of each wavelength of electromagnetic
radiation:
a. 632.8 nm (wavelength of red light from helium - neon laser)
b. 503 nm (wavelength of maximum solar radiation)
c. 0.052 nm (a wavelength contained in medical x - rays)
To calculate the frequency of electromagnetic radiation, we use the formula \( c = \lambda
u \), where \( c \) is the speed of light (\( c = 3.00 \times 10^8 \, \text{m/s} \)), \( \lambda \) is the wavelength, and \(
u \) is the frequency. We can rearrange this formula to solve for frequency: \(
u = \frac{c}{\lambda} \). Note that we need to convert the wavelength from nanometers (nm) to meters (m) since \( 1 \, \text{nm} = 10^{-9} \, \text{m} \).
Part (a): Wavelength \( \lambda = 632.8 \, \text{nm} \)
Step 1: Convert wavelength to meters
\( \lambda = 632.8 \, \text{nm} \times \frac{10^{-9} \, \text{m}}{1 \, \text{nm}} = 632.8 \times 10^{-9} \, \text{m} = 6.328 \times 10^{-7} \, \text{m} \)
Step 2: Calculate frequency using \(
u = \frac{c}{\lambda} \)
\(
u = \frac{3.00 \times 10^8 \, \text{m/s}}{6.328 \times 10^{-7} \, \text{m}} \approx 4.74 \times 10^{14} \, \text{Hz} \)
Part (b): Wavelength \( \lambda = 503 \, \text{nm} \)
Step 1: Convert wavelength to meters
\( \lambda = 503 \, \text{nm} \times \frac{10^{-9} \, \text{m}}{1 \, \text{nm}} = 503 \times 10^{-9} \, \text{m} = 5.03 \times 10^{-7} \, \text{m} \)
Step 2: Calculate frequency using \(
u = \frac{c}{\lambda} \)
\(
u = \frac{3.00 \times 10^8 \, \text{m/s}}{5.03 \times 10^{-7} \, \text{m}} \approx 5.96 \times 10^{14} \, \text{Hz} \)
Part (c): Wavelength \( \lambda = 0.052 \, \text{nm} \)
Step 1: Convert wavelength to meters
\( \lambda = 0.052 \, \text{nm} \times \frac{10^{-9} \, \text{m}}{1 \, \text{nm}} = 0.052 \times 10^{-9} \, \text{m} = 5.2 \times 10^{-11} \, \text{m} \)
Step 2: Calculate frequency using \(
u = \frac{c}{\lambda} \)
\(
u = \frac{3.00 \times 10^8 \, \text{m/s}}{5.2 \times 10^{-11} \, \text{m}} \approx 5.77 \times 10^{18} \, \text{Hz} \)
Final Answers:
- (a) \( \approx 4.74 \times 10^{14} \, \text{Hz} \)
- (b) \( \approx 5.96 \times 10^{14} \, \text{Hz} \)
- (c) \( \approx 5.77 \times 10^{18} \, \text{Hz} \)
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To calculate the frequency of electromagnetic radiation, we use the formula \( c = \lambda
u \), where \( c \) is the speed of light (\( c = 3.00 \times 10^8 \, \text{m/s} \)), \( \lambda \) is the wavelength, and \(
u \) is the frequency. We can rearrange this formula to solve for frequency: \(
u = \frac{c}{\lambda} \). Note that we need to convert the wavelength from nanometers (nm) to meters (m) since \( 1 \, \text{nm} = 10^{-9} \, \text{m} \).
Part (a): Wavelength \( \lambda = 632.8 \, \text{nm} \)
Step 1: Convert wavelength to meters
\( \lambda = 632.8 \, \text{nm} \times \frac{10^{-9} \, \text{m}}{1 \, \text{nm}} = 632.8 \times 10^{-9} \, \text{m} = 6.328 \times 10^{-7} \, \text{m} \)
Step 2: Calculate frequency using \(
u = \frac{c}{\lambda} \)
\(
u = \frac{3.00 \times 10^8 \, \text{m/s}}{6.328 \times 10^{-7} \, \text{m}} \approx 4.74 \times 10^{14} \, \text{Hz} \)
Part (b): Wavelength \( \lambda = 503 \, \text{nm} \)
Step 1: Convert wavelength to meters
\( \lambda = 503 \, \text{nm} \times \frac{10^{-9} \, \text{m}}{1 \, \text{nm}} = 503 \times 10^{-9} \, \text{m} = 5.03 \times 10^{-7} \, \text{m} \)
Step 2: Calculate frequency using \(
u = \frac{c}{\lambda} \)
\(
u = \frac{3.00 \times 10^8 \, \text{m/s}}{5.03 \times 10^{-7} \, \text{m}} \approx 5.96 \times 10^{14} \, \text{Hz} \)
Part (c): Wavelength \( \lambda = 0.052 \, \text{nm} \)
Step 1: Convert wavelength to meters
\( \lambda = 0.052 \, \text{nm} \times \frac{10^{-9} \, \text{m}}{1 \, \text{nm}} = 0.052 \times 10^{-9} \, \text{m} = 5.2 \times 10^{-11} \, \text{m} \)
Step 2: Calculate frequency using \(
u = \frac{c}{\lambda} \)
\(
u = \frac{3.00 \times 10^8 \, \text{m/s}}{5.2 \times 10^{-11} \, \text{m}} \approx 5.77 \times 10^{18} \, \text{Hz} \)
Final Answers:
- (a) \( \approx 4.74 \times 10^{14} \, \text{Hz} \)
- (b) \( \approx 5.96 \times 10^{14} \, \text{Hz} \)
- (c) \( \approx 5.77 \times 10^{18} \, \text{Hz} \)