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a bucket of water experiencing a gravitational force of 525 n is pulled…

Question

a bucket of water experiencing a gravitational force of 525 n is pulled up from a water well. the net force in the y - direction is 45 n; therefore, the magnitude of the force of tension is n.

Explanation:

Step1: Define the forces acting on the bucket

Let the gravitational force be $F_g = 525$ N (down - ward, negative direction) and the net force be $F_{net}=45$ N (up - ward, positive direction). Let the tension force be $T$. According to Newton's second law in the y - direction, $F_{net}=T - F_g$.

Step2: Solve for the tension force

We can re - arrange the formula $F_{net}=T - F_g$ to find $T$. Adding $F_g$ to both sides of the equation gives $T=F_{net}+F_g$.
Substitute $F_{net} = 45$ N and $F_g=525$ N into the formula: $T = 45+525$.
$T = 570$ N.

Answer:

570