Question

1. boyle’s law

$p_1v_1 = p_2v_2$ (solve for $p_1$)
$p_1$ = initial pressure
$v_1$ = initial volume
$p_2$ = final pressure
$v_2$ = final volume

Explanation:

Step1: Isolate $P_1$

Divide both sides by $V_1$.
$P_1V_1\div V_1 = P_2V_2\div V_1$

Step2: Simplify the equation

$P_1=\frac{P_2V_2}{V_1}$

Answer:

$P_1=\frac{P_2V_2}{V_1}$