Question

a block is pulled by a force of (112\text{ n}) directed at a (39.0^circ) angle from the horizontal.

what is the x-component of the force acting on the block?

(vec{f}_x = ? \text{ n})

Explanation:

⚡ Using what you learned: Vectors in Plane and Space (components, magnitude, direction)

Step 1: Identify the given values

$$ F = 112\text{ N} $$

$$ \theta = 39.0^\circ $$

Step 2: Calculate the horizontal component

$$ F_x = F \cos(\theta) $$

$$ F_x = 112 \cdot \cos(39.0^\circ) $$

$$ F_x \approx 112 \cdot 0.77715 $$

$$ F_x \approx 87.04\text{ N} $$

Answer:

87.0