Question

a bicyclist is traveling 10 m/s with an acceleration of 6 m/s². how fast is the bicyclist traveling at the end of 20 seconds? oa 20 m/s ob 26 m/s oc 110 m/s od 130 m/s

Explanation:

Step1: Identify the formula

Use the kinematic formula \(v = v_0+at\), where \(v_0\) is the initial velocity, \(a\) is the acceleration, and \(t\) is the time.

Step2: Substitute the values

Given \(v_0 = 10\space m/s\), \(a=6\space m/s^{2}\), and \(t = 20\space s\).
Substitute into the formula: \(v=10 + 6\times20\).

Step3: Calculate the result

First, calculate \(6\times20=120\). Then \(v=10 + 120\).

Answer:

D. \(130\space m/s\)