Question

a bicycle carrying a girl has a combined mass of 40 kg and is traveling at a velocity of 8 m/s. what is the kinetic energy of the girl on bicycle? (dont forget units!)
1response
$ke = \frac{mv^{2}}{2}$ or $ke = \frac{1}{2}mv^{2}$ $pe = mgh$ where $g = 9.8 m/s^{2}$ $pe_{max} = ke_{max}$
5031j
2560j
1280j
1820j

Explanation:

Step1: Identify the formula for kinetic energy

The formula for kinetic energy is \( KE=\frac{1}{2}mv^{2} \), where \( m \) is the mass and \( v \) is the velocity.

Step2: Substitute the given values into the formula

Given \( m = 40\space kg \) and \( v=8\space m/s \).
Substitute into \( KE=\frac{1}{2}\times40\times8^{2} \).
First calculate \( 8^{2}=64 \).
Then \( \frac{1}{2}\times40 = 20 \).
Finally, \( KE=20\times64=1280\space J \).

Answer:

1280J