Question

below. write your answer using only positive exponents. \\(\frac{10^{0}r^{-11}s}{3^{2}}\\) \\(\frac{s}{9r^{11}}\\) \\(9r^{11}s\\) \\(\frac{9s}{r^{11}}\\) \\(\frac{r^{11}}{9s}\\)

Explanation:

Step1: Simplify \(10^0\)

Any non - zero number to the power of 0 is 1, so \(10^0 = 1\). The expression becomes \(\frac{1\times r^{- 11}s}{3^2}\).

Step2: Simplify \(3^2\)

\(3^2=9\), so the expression is \(\frac{r^{-11}s}{9}\).

Step3: Use the negative exponent rule

The negative exponent rule states that \(a^{-n}=\frac{1}{a^{n}}\) (or \(\frac{1}{a^{-n}}=a^{n}\)). So \(r^{-11}=\frac{1}{r^{11}}\), then \(\frac{r^{-11}s}{9}=\frac{s}{9r^{11}}\).

Answer:

A. \(\frac{s}{9r^{11}}\)