Question

a basketball has a mass of 1 kg and is traveling 12 m/s. what would happen to the velocity if the momentum of the basketball were cut in half? it would be the same. it would be doubled. it would be tripled. it would be cut in half.

Explanation:

Step1: Recall the momentum formula

The formula for momentum is \(p = mv\), where \(p\) is momentum, \(m\) is mass, and \(v\) is velocity.

Step2: Analyze the relationship between momentum and velocity

Given \(m = 1\space kg\) (constant), initially \(p_1=mv_1\) with \(v_1 = 12\space m/s\). If \(p_2=\frac{1}{2}p_1\), then \(\frac{1}{2}p_1=mv_2\). Substituting \(p_1 = mv_1\) into \(\frac{1}{2}p_1=mv_2\), we get \(\frac{1}{2}(mv_1)=mv_2\). Since \(m
eq0\), we can cancel \(m\) from both sides of the equation. So \(\frac{1}{2}v_1 = v_2\).

Answer:

It would be cut in half.