Question

a ball is rolling down a hill. at the initial point of measurement, the ball is traveling at 1.3 m/s. after 15 seconds, the ball is measured to be traveling at 4.8 m/s. what is the acceleration of the ball? 0.23 m/s² 1.3 m/s² 3.5 m/s² 4.8 m/s²

Explanation:

Step1: Recall the acceleration formula

The formula for acceleration \(a=\frac{v - u}{t}\), where \(v\) is the final velocity, \(u\) is the initial velocity, and \(t\) is the time.

Step2: Identify the values

Given \(u = 1.3\ m/s\), \(v=4.8\ m/s\), and \(t = 15\ s\).

Step3: Substitute the values into the formula

\(a=\frac{4.8 - 1.3}{15}=\frac{3.5}{15}\approx0.23\ m/s^{2}\)

Answer:

\(0.23\ m/s^{2}\) (the first option)