Question

the average value of a full - wave rectified voltage with a peak value of 9.8 is answer: choose... choose... v

Explanation:

Step1: Recall the formula for average value of full - wave rectified voltage

The formula for the average value \(V_{avg}\) of a full - wave rectified sinusoidal voltage is \(V_{avg}=\frac{2V_m}{\pi}\), where \(V_m\) is the peak value of the voltage.

Step2: Substitute the given peak value into the formula

Given \(V_m = 9.8\). Then \(V_{avg}=\frac{2\times9.8}{\pi}\).

Step3: Calculate the value

We know that \(\pi\approx3.14\). So \(V_{avg}=\frac{19.6}{3.14}\approx6.24\).

Answer:

$6.24$