Question

1. the average acceleration of a space shuttle after takeoff of 29 m/s² upwards. what is the shuttles velocity after a period of 12 s? (2)

Explanation:

Step1: Recall the formula for velocity

The formula for velocity \(v = v_0+at\). Assuming the initial velocity \(v_0 = 0\) (take - off from rest), \(a = 29\ m/s^{2}\), and \(t=12\ s\)

Step2: Substitute the values into the formula

\(v=0 + 29\times12\)
\(v = 29\times12=348\ m/s\)

Answer:

\(348\ m/s\)