Question

assume a phenotype is determined by one gene with a dominant allele and a recessive allele. if one parent is heterozygous and the other parent is homozygous dominant, what is the probability of producing a homozygous recessive offspring?
○ 0%
○ 25%
○ 50%
○ 75%
○ 100%

Explanation:

Step1: Define alleles

Let the dominant allele be \(A\) and the recessive allele be \(a\). One parent is heterozygous (\(Aa\)) and the other is homozygous dominant (\(AA\)).

Step2: Do the cross

Using the Punnett square method, the cross \(Aa\times AA\) gives the following offspring genotypes: \(AA\) and \(Aa\).

Step3: Analyze the results

There are no offspring with the \(aa\) (homozygous recessive) genotype. So the probability of homozygous recessive offspring is \(0\%\).

Answer:

A. 0%