Question

1. assume that one of squidwards sons, who is heterozygous for the light blue body color, married a girl that was also heterozygous. create a punnett square to show the possibilities that would result if they had children.

a. list the possible genotypes and phenotypes for their children.
b. what are the chances of a child with light blue skin? ____%
c. what are the chances of a child with light green skin? ____%

Explanation:

Step1: Create Punnett square

Let \( B \) represent the allele for light - blue body color and \( b \) represent the allele for light - green body color.
The father is \( Bb \) and the mother is \( Bb \).
The Punnett square is:

	\( B \)	\( b \)
\( b \)	\( Bb \)	\( bb \)

Step2: Determine genotypes and phenotypes

• Genotypes:
• \( BB: Bb: bb=1:2:1 \)
• Phenotypes:
• \( BB \) and \( Bb \) show light - blue body color (dominant trait). \( bb \) shows light - green body color (recessive trait).
• The probability of light - blue body color (\( BB + Bb \)): \(\frac{1 + 2}{4}=\frac{3}{4}=75\%\)
• The probability of light - green body color (\( bb \)): \(\frac{1}{4} = 25\%\)

Answer:

A. Genotypes: \( BB \), \( Bb \), \( bb \). Phenotypes: Light - blue body color (\( BB \), \( Bb \)), Light - green body color (\( bb \))
B. \( 75\)
C. \( 25\)