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arrastra y suelta las expresiones condicionales para obtener un código …

Question

arrastra y suelta las expresiones condicionales para obtener un código que imprima *** en la consola (nota: no se utilizarán todas las cajas de código.)
height = 64 // 2
if height > 0:
print(\**\)
elif :
print(\****\)
elif :
print(\*****\)

Explanation:

To solve this, we analyze the code structure and the conditional expressions:

Step 1: Analyze the first elif

The first print (inside if height > 0) outputs . The next print outputs , so we need a condition where height is equal to some value (or in a range) that triggers . Looking at the initial calculation height = 84 // 2 = 42 (wait, no—wait, 84 // 2 is 42? Wait, maybe a typo, but the key is the conditions. Wait, the first if is height > 0, then elif for height == 0? No, wait, the output for the second print is *, so maybe the condition is height == 0? No, let's re-examine.

Wait, the code starts with height = 84 // 2 (which is 42). Then if height > 0: print(""). Then elif [condition]: print(""), then elif [condition]: print("***").

Wait, maybe the intended logic is:

  • If height > 0, print **
  • If height == 0, print *** (no, that doesn't make sense). Wait, maybe the conditions are about the value of height relative to 0. Wait, the left side has height < 0, height > 0, height == 0, height <= 0.

Wait, the first if is height > 0, so the next elif should be a condition that is mutually exclusive. Let's think:

  • if height > 0 → print **
  • elif height == 0 → print ***
  • elif height < 0 → print ****

But let's check the left-side options. The left has height < 0, height > 0 (used in if), height == 0, height <= 0.

Wait, maybe the first elif is height == 0 (to print ), and the second elif is height < 0 (to print *).

So:

  1. First elif (for print("***")): height == 0
  2. Second elif (for print("****")): height < 0

But let's confirm. The initial height = 84 // 2 = 42, so height > 0 is true, so it would print **. But maybe the problem has a different setup. Alternatively, maybe the height calculation is height = 84 // 2 (42), but the conditions are about height relative to 0.

Wait, perhaps the correct conditions are:

  • elif height == 0: → print ***
  • elif height < 0: → print ****

So the first elif (for ) uses height == 0, and the second elif (for *) uses height < 0.

But let's check the left-side options. The left has:

  • height < 0
  • height > 0 (used in if)
  • height == 0
  • height <= 0

So:

  1. First elif (print ***): height == 0
  2. Second elif (print ****): height < 0

Thus, the first elif box (for print("")) should have height == 0, and the second elif box (for print("*")) should have height < 0.

But let's verify the code flow:

  • height = 84 // 2 → 42 (so height > 0 is true, so print("") runs. Then the elif conditions are checked, but since height > 0 is true, the elifs are skipped. But if height were 0, elif height == 0 would run and print . If height were negative, elif height < 0 would run and print ***.

So the correct drag-and-drop is:

  • First elif (print ***): height == 0
  • Second elif (print ****): height < 0

(Note: The initial height = 84 // 2 is 42, so the if condition height > 0 is true, and the elifs are not executed here. But the problem is about arranging the conditions for the code structure.)

Answer:

To solve this, we analyze the code structure and the conditional expressions:

Step 1: Analyze the first elif

The first print (inside if height > 0) outputs . The next print outputs , so we need a condition where height is equal to some value (or in a range) that triggers . Looking at the initial calculation height = 84 // 2 = 42 (wait, no—wait, 84 // 2 is 42? Wait, maybe a typo, but the key is the conditions. Wait, the first if is height > 0, then elif for height == 0? No, wait, the output for the second print is *, so maybe the condition is height == 0? No, let's re-examine.

Wait, the code starts with height = 84 // 2 (which is 42). Then if height > 0: print(""). Then elif [condition]: print(""), then elif [condition]: print("***").

Wait, maybe the intended logic is:

  • If height > 0, print **
  • If height == 0, print *** (no, that doesn't make sense). Wait, maybe the conditions are about the value of height relative to 0. Wait, the left side has height < 0, height > 0, height == 0, height <= 0.

Wait, the first if is height > 0, so the next elif should be a condition that is mutually exclusive. Let's think:

  • if height > 0 → print **
  • elif height == 0 → print ***
  • elif height < 0 → print ****

But let's check the left-side options. The left has height < 0, height > 0 (used in if), height == 0, height <= 0.

Wait, maybe the first elif is height == 0 (to print ), and the second elif is height < 0 (to print *).

So:

  1. First elif (for print("***")): height == 0
  2. Second elif (for print("****")): height < 0

But let's confirm. The initial height = 84 // 2 = 42, so height > 0 is true, so it would print **. But maybe the problem has a different setup. Alternatively, maybe the height calculation is height = 84 // 2 (42), but the conditions are about height relative to 0.

Wait, perhaps the correct conditions are:

  • elif height == 0: → print ***
  • elif height < 0: → print ****

So the first elif (for ) uses height == 0, and the second elif (for *) uses height < 0.

But let's check the left-side options. The left has:

  • height < 0
  • height > 0 (used in if)
  • height == 0
  • height <= 0

So:

  1. First elif (print ***): height == 0
  2. Second elif (print ****): height < 0

Thus, the first elif box (for print("")) should have height == 0, and the second elif box (for print("*")) should have height < 0.

But let's verify the code flow:

  • height = 84 // 2 → 42 (so height > 0 is true, so print("") runs. Then the elif conditions are checked, but since height > 0 is true, the elifs are skipped. But if height were 0, elif height == 0 would run and print . If height were negative, elif height < 0 would run and print ***.

So the correct drag-and-drop is:

  • First elif (print ***): height == 0
  • Second elif (print ****): height < 0

(Note: The initial height = 84 // 2 is 42, so the if condition height > 0 is true, and the elifs are not executed here. But the problem is about arranging the conditions for the code structure.)