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Question
applying the converse of the isosceles triangle theorem consider isosceles △xyz. what is the value of n? what is the measure of leg xy? ft what is the measure of leg xz? ft
Step1: Use the converse of the isosceles triangle theorem
Since \(\triangle XYZ\) is isosceles and \(\angle Y=\angle Z\), then \(XY = XZ\). So, \(9n + 12=15n-6\).
Step2: Solve the equation for \(n\)
Subtract \(9n\) from both sides: \(12 = 6n-6\).
Add \(6\) to both sides: \(18=6n\).
Divide both sides by \(6\): \(n = 3\).
Step3: Find the length of \(XY\)
Substitute \(n = 3\) into \(9n + 12\): \(9\times3+12=27 + 12=39\).
Step4: Find the length of \(XZ\)
Substitute \(n = 3\) into \(15n-6\): \(15\times3-6=45 - 6=39\).
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The value of \(n\) is \(3\).
The measure of leg \(XY\) is \(39\) ft.
The measure of leg \(XZ\) is \(39\) ft.