Question

answer the questions below.
(a) the area of a rectangular field is 8712 m².
if the width of the field is 88 m, what is its length?
length of the field:
(b) the perimeter of a rectangular painting is 312 cm.
if the length of the painting is 83 cm, what is its width?
width of the painting:

Explanation:

(a)

Step1: Recall the area formula of a rectangle

The area formula of a rectangle is \(A = l\times w\), where \(A\) is the area, \(l\) is the length, and \(w\) is the width. We need to solve for \(l\), so \(l=\frac{A}{w}\).

Step2: Substitute the given values

Given \(A = 8712\space m^{2}\) and \(w = 88\space m\). Then \(l=\frac{8712}{88}\).

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(b)

Step1: Recall the perimeter formula of a rectangle

The perimeter formula of a rectangle is \(P=2(l + w)\), where \(P\) is the perimeter, \(l\) is the length, and \(w\) is the width. First, we can rewrite the formula for \(w\) as \(w=\frac{P}{2}-l\).

Step2: Substitute the given values

Given \(P = 312\space cm\) and \(l = 83\space cm\). Then \(w=\frac{312}{2}-83\).

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Answer:

(a) \(99\space m\)
(b) \(73\space cm\)