Question

the amount of potential energy, p, an object has is equal to the product of its mass, m, its height off the ground, h, and the gravitational constant, g. this can be modeled by the equation p = mgh. what is the equivalent equation solved for h? options: pm g = h; \\(\frac{p}{(\frac{m}{g})} = h\\); \\(\frac{p}{mg} = h\\); \\(\frac{mgp}{g} = h\\)

Explanation:

Step1: Start with the given equation

We have the equation for potential energy: \( P = mgh \). Our goal is to solve for \( h \).

Step2: Isolate \( h \) by dividing both sides

To isolate \( h \), we divide both sides of the equation \( P = mgh \) by \( mg \) (assuming \( m
eq 0 \) and \( g
eq 0 \)).
Dividing both sides by \( mg \), we get:

$$ \frac{P}{mg} = \frac{mgh}{mg} $$

Simplifying the right - hand side, the \( m \) and \( g \) in the numerator and denominator cancel out, leaving us with:

$$ \frac{P}{mg}=h $$

Answer:

\(\boldsymbol{\frac{P}{mg}=h}\) (the third option from the top)