alessandro wrote the quadratic equation $-6 = x^2 + 4x - 1$ in standard form. what is the value of $c$ in his new equation?

$c = -6$
$c = -1$
$c = 5$
$c = 7$

Question

alessandro wrote the quadratic equation $-6 = x^2 + 4x - 1$ in standard form. what is the value of $c$ in his new equation?

$c = -6$
$c = -1$
$c = 5$
$c = 7$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Quadratic Equations" ], "new_concepts": [], "current_concepts": [ "Quadratic Equations", "Standard Form of Quadratic Equations" ] } ## Write the given equation $$-6 = x^2 + 4x - 1$$ ## Rearrange to standard form $ax^2 + bx + c = 0$ $$ \begin{aligned} 0 &= x^2 + 4x - 1 + 6 \ 0 &= x^2 + 4x + 5 \end{aligned} $$ ## Identify the value of $c$ $$ \begin{aligned} &a = 1 \ &b = 4 \ &c = 5 \end{aligned} $$

$c = -6$

$c = -1$

$c = 5$

$c = 7$

{ "subject": "Mathematics", "question_type": "Multiple Choice", "knowledge_point": [ "Mathematics", "Algebra", "Standard Form of Quadratic Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Write the given equation

Rearrange to standard form \(ax^2 + bx + c = 0\)

Identify the value of \(c\)

Answer: