Question

agent bourne transferred classified files from the cia mainframe into his flash drive. the drive had 36.5 megabytes on it before the transfer, and the transfer happened at a constant rate. after 125 seconds, there were 549 megabytes on the drive. the drive had a maximum capacity of 1000 megabytes.
what was the speed of the transfer?
megabytes per second
how long did it take the drive to be completely full?
seconds
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Explanation:

Step1: Calculate transferred data

The initial data is 36.5 MB, and after 125 seconds, it's 549 MB. So transferred data is \( 549 - 36.5 = 512.5 \) MB.

Step2: Find transfer speed

Speed = transferred data / time. So \( \frac{512.5}{125} = 4.1 \) megabytes per second.

Step3: Calculate remaining space

Maximum capacity is 1000 MB, initial is 36.5 MB. Remaining space: \( 1000 - 36.5 = 963.5 \) MB.

Step4: Time to fill remaining space

Time = remaining space / speed. So \( \frac{963.5}{4.1} = 235 \) seconds. Total time: 125 + 235 = 360 seconds? Wait, no: Wait, the time to fill from start? Wait, no, the question is "how long did it take the drive to be completely full" – from when? From the start? Wait, initial was 36.5, then after 125 seconds, it's 549. Wait, maybe better: total data to transfer to fill is \( 1000 - 36.5 = 963.5 \) MB. Speed is 4.1 MB/s. So time is \( \frac{963.5}{4.1} = 235 \) seconds? Wait, no, wait: Wait, the first part: speed is 4.1 MB/s. Then, the time to fill the drive (from the start) would be time to transfer (1000 - 36.5) MB at 4.1 MB/s. So \( (1000 - 36.5) / 4.1 = 963.5 / 4.1 = 235 \) seconds? Wait, but let's check the first part again. Transferred in 125 seconds: 549 - 36.5 = 512.5. 512.5 / 125 = 4.1. Correct. Then, to fill the drive, we need to transfer 1000 - 36.5 = 963.5 MB. At 4.1 MB/s, time is 963.5 / 4.1 = 235 seconds. Wait, but maybe the question is from the start? Wait, the initial state is 36.5 MB. So the time to fill the drive (from having 36.5 MB) would be (1000 - 36.5)/4.1 = 235 seconds. But if we consider from the start of the transfer (when he started transferring), then total time is 125 + 235? No, wait, the transfer was happening at constant rate. So the time to fill the drive (from the moment he started transferring) would be total data needed (1000 - 36.5) divided by speed, which is 235 seconds? Wait, no, 1000 - 36.5 is 963.5, divided by 4.1 is 235. So total time from start (when the drive had 36.5 MB) to full is 235 seconds? Wait, no, because after 125 seconds, it's at 549. So from start (36.5 MB) to full (1000 MB) is (1000 - 36.5)/4.1 = 235 seconds. Wait, but 36.5 + 4.1*235 = 36.5 + 963.5 = 1000. Correct. So the first answer (speed) is 4.1, the second (time to fill) is 235 seconds? Wait, but let's check again. Wait, the question "how long did it take the drive to be completely full" – maybe from the start of the transfer? Wait, the transfer started, and after 125 seconds, it's at 549. So the total time to fill the drive (from when the transfer started) would be time to transfer (1000 - 36.5) MB at 4.1 MB/s, which is 235 seconds. So:

First answer: 4.1 megabytes per second.

Second answer: 235 seconds? Wait, no, wait: Wait, 1000 - 36.5 is 963.5. 963.5 divided by 4.1 is 235. So yes.

Answer:

Speed: 4.1 megabytes per second.

Time to fill: 235 seconds.