Question

after a day of testing race cars, you decide to take your own 1453.5 kg car onto the test track. while moving down the track at 11.9 m/s, you suddenly accelerate to 27.5 m/s in 15.6 s.
what average net force have you applied to the car during that time?
answer in units of n. answer in units of n.

Explanation:

Step1: Calculate the acceleration

Use the formula \(a=\frac{v - u}{t}\), where \(v = 27.5\ m/s\), \(u = 11.9\ m/s\), and \(t = 15.6\ s\).

$$a=\frac{27.5 - 11.9}{15.6}=\frac{15.6}{15.6}=1\ m/s^{2}$$

Step2: Calculate the force

Use Newton's second law \(F = ma\), where \(m = 1453.5\ kg\) and \(a = 1\ m/s^{2}\).

$$F=1453.5\times1 = 1453.5\ N$$

Answer:

1. \(1453.5\)