ac is tangent to circle o at point c. what is the measure of ∠oac? show calculator

Question

Accepted Answer

# Explanation:
## Step1: Use the property of tangent to a circle
A tangent to a circle is perpendicular to the radius at the point of tangency. So, $ \angle OCA = 90^{\circ}$.
## Step2: Use the angle - sum property of a triangle
In $\triangle OAC$, we know that the sum of angles in a triangle is $180^{\circ}$. Let $ \angle OAC=x$. We have $x + 63^{\circ}+90^{\circ}=180^{\circ}$.
## Step3: Solve for $x$
$$
\begin{align*}
x&=180^{\circ}-(90^{\circ} + 63^{\circ})\
x&=180^{\circ}-153^{\circ}\
x& = 27^{\circ}
\end{align*}
$$

# Answer:
$27^{\circ}$

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step1: Use the property of tangent to a circle

Step2: Use the angle - sum property of a triangle

Step3: Solve for \(x\)

Answer: