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abeled angle. 8 (7x + 10)° (15x + 16)° x = $\frac{4}{3}$ (7x + 10)° = _…

Question

abeled angle. 8 (7x + 10)° (15x + 16)° x = $\frac{4}{3}$ (7x + 10)° = __ ° (15x + 16)° = __ °

Explanation:

Step1: Substitute $x = \frac{4}{3}$ into $(7x + 10)$

$7\times\frac{4}{3}+ 10=\frac{28}{3}+10=\frac{28 + 30}{3}=\frac{58}{3}\approx19.33$

Step2: Substitute $x=\frac{4}{3}$ into $(15x + 16)$

$15\times\frac{4}{3}+16 = 20 + 16=36$

Answer:

$(7x + 10)^{\circ}=\frac{58}{3}^{\circ}\approx19.33^{\circ}$
$(15x + 16)^{\circ}=36^{\circ}$