Question

1. ab is tangent to circle c. find ac to two decimal places. a 19 6 b 19.00 19.92 25.00 18.03

Explanation:

Step1: Identify right triangle ABC

AB is tangent to circle C, so $\angle ABC = 90^\circ$. BC = 6 (radius), AB = 19.

Step2: Apply Pythagorean theorem

$AC^2 = AB^2 + BC^2$
$AC^2 = 19^2 + 6^2 = 361 + 36 = 397$
$AC = \sqrt{397} \approx 19.92$

Answer:

19.92