Question

8y + 12 = 12 + 7y

y = 0

you can substitute 0 for y to make
the original equation true.

8y + 12 = 12 + 7y
8(0) + 12 = 12 + 7(0)
0 + 12 = 12 + 0
12 = 12 true

how many solutions does 8y + 12 = 12 + 7y have?

no solution
one solution
infinitely many solutions

Explanation:

Step1: Solve the equation \(8y + 12 = 12 + 7y\)

Subtract \(7y\) from both sides: \(8y - 7y+ 12 = 12 + 7y - 7y\), which simplifies to \(y + 12 = 12\).

Step2: Isolate \(y\)

Subtract 12 from both sides: \(y + 12 - 12 = 12 - 12\), so \(y = 0\).
Since we found a unique value (\(y = 0\)) that satisfies the equation, the equation has one solution.

Answer:

B. one solution