Question

1. a 855 kg car pushes on the road with 5450 n of force. what is the magnitude of the force the road exerts back on the car, and what is the acceleration of the car? 1324 n, 4.57 m/s² 855 n, 7.68 m/s² 5450 n, 6.37 m/s² 4595 n, 6.37 m/s²

Explanation:

Step1: Determine the force exerted by the road

According to Newton's third law of motion (action - reaction), the force the road exerts on the car \(F_{road}\) is equal in magnitude to the force the car exerts on the road. So \(F_{road}=5450\ N\).

Step2: Calculate the acceleration of the car

Use Newton's second law \(F = ma\), where \(F\) is the net force (here \(F = F_{road}\)), \(m = 855\ kg\) is the mass of the car, and \(a\) is the acceleration. Rearranging for \(a\), we get \(a=\frac{F}{m}\). Substitute \(F = 5450\ N\) and \(m = 855\ kg\) into the formula: \(a=\frac{5450}{855}\approx6.37\ m/s^{2}\)

Answer:

C. \(5450\ N, 6.37\ m/s^{2}\)