Question

a 75 kg hockey player is skating at 4 m/s and increases to 7 m/s over 3 seconds. what force is applied?

Explanation:

Step1: Calculate acceleration

Acceleration formula: $a=\frac{v - u}{t}$, where $v = 7\ m/s$, $u = 4\ m/s$, $t = 3\ s$.
$a=\frac{7 - 4}{3}=\frac{3}{3}=1\ m/s^{2}$

Step2: Calculate force

Force formula: $F = ma$, where $m = 75\ kg$, $a = 1\ m/s^{2}$.
$F=75\times1 = 75\ N$

Answer:

$75\ N$