Question

a 75.0kg bicyclist (including the bicycle) is pedaling to the right, generating a 250n force. she is experiencing a 40.0n drag. neglect any friction impeding her motion. how many forces are acting on the bicyclist? 4 what is the magnitude of the net force on the bicyclist? unit what is the magnitude of her acceleration? unit describe her speed:

Explanation:

Sub - question 1: How many forces are acting on the bicyclist?

To determine the number of forces on the bicyclist, we consider the following: gravitational force (weight) pulling down, normal force from the ground pushing up, the applied force from pedaling to the right, and the drag force opposing the motion (to the left). So there are 4 forces.

Step 1: Identify the horizontal forces

The applied force \( F_{applied}=250N \) (to the right) and the drag force \( F_{drag} = 40.0N\) (to the left). The vertical forces (gravity and normal force) are equal in magnitude and opposite in direction, so they cancel out.

Step 2: Calculate the net horizontal force

The net force \( F_{net}=F_{applied}-F_{drag}\) (since they are in opposite directions). Substituting the values, we get \( F_{net}=250N - 40.0N=210N\).

Step 1: Recall Newton's second law

Newton's second law is \( F = ma\), where \( F\) is the net force, \( m\) is the mass, and \( a\) is the acceleration. We know \( F_{net}=210N\) and \( m = 75.0kg\).

Step 2: Solve for acceleration

Rearranging the formula for \( a\), we get \( a=\frac{F_{net}}{m}\). Substituting the values, \( a=\frac{210N}{75.0kg}=2.8m/s^{2}\).

Answer:

4

Sub - question 2: What is the magnitude of the net force on the bicyclist?