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69. ( k^2 + 24k + 144 = 0 )

Question

  1. ( k^2 + 24k + 144 = 0 )

Explanation:

Step1: Recognize perfect square trinomial

$k^2 + 24k + 144 = (k+12)^2$

Step2: Set factor equal to 0

$(k+12)^2 = 0$

Step3: Solve for k

$k+12=0$

Answer:

$k=-12$ (repeated root)