Question

a 500n block is lifted 25m. how much work was done? 525j 12,500j 120j 460j

Explanation:

Step1: Recall the formula for work

Work \( W = F\times d\), where \(F\) is the force and \(d\) is the distance.

Step2: Substitute the given values

Given \(F = 500N\) and \(d=25m\). Then \(W=500\times25\).

Step3: Calculate the product

\(500\times25=(5\times10^{2})\times(2.5\times10^{1})=(5\times2.5)\times(10^{2 + 1})=12.5\times10^{3}=12500J\)

Answer:

12,500J