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-5(3x - 6) + 5 ≥ -25

Question

-5(3x - 6) + 5 ≥ -25

Explanation:

Step1: Distribute -5

$-5(3x - 6) = -15x + 30$, so the inequality becomes $-15x + 30 + 5 \geq -25$.

Step2: Combine like terms

$30 + 5 = 35$, so we have $-15x + 35 \geq -25$.

Step3: Subtract 35 from both sides

$-15x \geq -25 - 35$, which simplifies to $-15x \geq -60$.

Step4: Divide both sides by -15 (and reverse inequality)

When dividing by a negative number, the inequality sign flips. So $x \leq \frac{-60}{-15}$, which gives $x \leq 4$.

Answer:

$x \leq 4$