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Question
- \\( \sin (-5)+5= \\)
- \\( \cos (-28)-1= \\)
- \\( \tan (25) \cdot 3= \\)
Step1: Calculate \(\sin(-5)+5\)
We know that \(\sin(-x)=-\sin x\). But here \(x = 5\) (in radians). Using a calculator, \(\sin(5)\approx - 0.9589\). Then \(\sin(-5)+5=- \sin(5)+5\approx-(- 0.9589)+5 = 0.9589 + 5=5.9589\approx5.96\)
Step2: Calculate \(\cos(-28)-1\)
Since \(\cos(-x)=\cos x\), for \(x = 28\) (in radians), \(\cos(28)\approx0.9370\). Then \(\cos(-28)-1=\cos(28)-1\approx0.9370 - 1=-0.063\)
Step3: Calculate \(\tan(25)\cdot3\)
Here \(25\) is in radians. \(\tan(25)\approx-0.1335\). Then \(\tan(25)\cdot3\approx(-0.1335)\times3=-0.4005\approx - 0.40\)
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- \(5.96\)
- \(-0.063\)
- \(-0.40\)