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3. \\begin{cases} y = x - 1 \\\\ x - 4y = 16 \\end{cases}

Question

  1. \
$$\begin{cases} y = x - 1 \\\\ x - 4y = 16 \\end{cases}$$

Explanation:

Step1: Substitute \( y = x - 1 \) into \( x - 4y = 16 \)

Substitute \( y \) in the second equation: \( x - 4(x - 1) = 16 \)

Step2: Simplify the equation

Expand and simplify: \( x - 4x + 4 = 16 \) → \( -3x + 4 = 16 \)
Subtract 4: \( -3x = 12 \)
Divide by -3: \( x = -4 \)

Step3: Find \( y \) using \( y = x - 1 \)

Substitute \( x = -4 \): \( y = -4 - 1 = -5 \)

Answer:

The solution to the system is \( x = -4 \), \( y = -5 \) (or the ordered pair \((-4, -5)\))