QUESTION IMAGE
Question
- z is the midpoint of \\( \overline { v x } \\) and \\( \overline { w y } \\). complete the proof that \\( \triangle v y z \cong \triangle x w z \\).
| statement | reason |
|---|---|
| 2 | \\( z \\) is the midpoint of \\( \overline { w y } \\) |
| 3 | \\( \overline { v z } \cong \overline { x z } \\) |
| 4 | \\( \overline { w z } \cong \overline { y z } \\) |
| 5 | \\( \angle v z y \cong \angle w z x \\) |
| 6 | \\( \triangle v y z \cong \triangle x w z \\) |
Step1: Midpoint definition
Since \(Z\) is the midpoint of \(\overline{VX}\), by the definition of a midpoint, \(VZ = XZ\).
Step2: Midpoint definition
Since \(Z\) is the midpoint of \(\overline{WY}\), by the definition of a midpoint, \(WZ = YZ\).
Step3: Vertical angles
\(\angle VZY\) and \(\angle WZX\) are vertical angles. By the vertical angles theorem, \(\angle VZY\cong\angle WZX\).
Step4: SAS congruence
In \(\triangle VYZ\) and \(\triangle XWZ\), we have \(VZ = XZ\) (from step 1), \(WZ = YZ\) (from step 2), and \(\angle VZY\cong\angle WZX\) (from step 3). By the Side - Angle - Side (SAS) congruence criterion, \(\triangle VYZ\cong\triangle XWZ\).
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- Given
- Given
- Definition of midpoint
- Definition of midpoint
- Vertical angles theorem
- SAS (Side - Angle - Side) congruence criterion