Question

1. \

$$\begin{cases} 3x - 4y = -14 \\\\ 3x + 2y = -2 \\end{cases}$$

Explanation:

Step1: Subtract the two equations

Subtract the first equation \(3x - 4y = -14\) from the second equation \(3x + 2y = -2\) to eliminate \(x\).

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Step2: Solve for \(y\)

Divide both sides of \(6y = 12\) by 6:

$$ y = \frac{12}{6} = 2 $$

Step3: Substitute \(y = 2\) into one of the original equations

Substitute \(y = 2\) into \(3x + 2y = -2\):

$$ 3x + 2(2) = -2\\ 3x + 4 = -2 $$

Step4: Solve for \(x\)

Subtract 4 from both sides:

$$ 3x = -2 - 4 = -6 $$

Divide both sides by 3:

$$ x = \frac{-6}{3} = -2 $$

Answer:

\(x = -2\), \(y = 2\)